Foot pounds to Megaelectronvolts calculator

Foot pounds to Megaelectronvolts Conversion Table

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• Foot pound (1.36 J)

  The foot pound-force (symbol: ft⋅lbf or ft⋅lb) is a unit of work or energy in the Engineering and Gravitational Systems in United States customary and imperial units of measure. It is the energy transferred upon applying a force of one pound-force (lbf) through a linear displacement of one foot. The corresponding SI unit is the joule. The foot-pound is often used to specify the muzzle energy of a bullet in small arms ballistics, particularly in the United States.

• Megaelectronvolt (0.00000000000016 J)

  In physics, the electronvolt (symbol eV, also written electron-volt and electron volt) is a unit of energy equal to approximately 1.6×10−19 joules (symbol J) in SI units. By definition, it is the amount of energy gained (or lost) by the charge of a single electron moving across an electric potential difference of one volt. Hence, it has a value of one volt, 1 J/C, multiplied by the electron's elementary charge e, 1.6021766208(98)×10−19 C. Therefore, one electronvolt is equal to 1.6021766208(98)×10−19 J. The electronvolt is not a SI unit, and its definition is empirical (unlike the litre, the light-year and other such non-SI units), where its value in SI units must be obtained experimentally.